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5x=6.25x^2
We move all terms to the left:
5x-(6.25x^2)=0
We get rid of parentheses
-6.25x^2+5x=0
a = -6.25; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-6.25)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-6.25}=\frac{-10}{-12.5} =5/6.25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-6.25}=\frac{0}{-12.5} =0 $
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